Question

a bullet is fired from a gun at a speed of 20 m/s of mass of bullet is 50 g. and mass of gun is 3 kg . the recoil velocity of the gun is

please give me answers fast​

Answer 1

Explanation:

Newton's third law says that every action has an equal and opposite reaction. Using this, we can say that momentum of the bullet will be equal to the momentum of the gun. So,the recoil velocity will be 1.5m/s.

Answer 2

Answer:

Mass of bullet, m=100g=

1000

100

kg=

10

1

kg

Velocity of bullet, v=100ms

−1

Mass of gun, M=20kg

Let recoil velocity of gun =V

Before firing, the system (gun+bullet) is at rest, therefore, initial momentum of the system =0

Final momentum of the system = momentum of bullet + momentum of gun

=mv+MV=

10

1

×100+20V=10+20V

Applying law of conservation of momentum, Final momentum = Initial momentum

i.e., 10+20V=0

20V=−10

or V=−

20

10

=−0.5ms

−1

.

Negative sign shows that the direction of recoil velocity of the gun is opposite to the direction of the velocity of the bullet.