a bullet is fired from a gun with a speed of 100meterpersecond in a direction of 30° above the horizontal calculate the maximum height,time of flight, horizontal range of the bullet ?
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Step-by-step explanation:
Range, R=3km
Angle of projection, =30
o
Acceleration due to gravity, g=9.8m/s
2
Horizontal range for the projection velocity u
0
, is given by the relation:
R=
g
u
o
2
Sin 2θ
3=
g
u
o
2
Sin 60
0
g
u
o
2
=2
3
.......(i)
The maximum range (Rmax) is achieved by the bullet when it is fired at an angle of 45 with the horizontal, that is, Rmax = u
o
2
/ g ....(ii)
On comparing equations (i) and (ii), we get:
R
max
=2×1.732=3.46 km
Hence, the bullet will not hit a target 5 km away.
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a bullet is fired from a gun with a speed of 100meterpersecond in a direction of 30° above the horizontal calculate the maximum height,time of flight, horizontal range of the bullet ?
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