A bullet is fired from a gun with a velocity of 490m/s at 30degrees with the horizontal. What is the horizontal range and maximum height attained by the bullet
Answers
Answered by
1
Answer:
Harry Sharp, former Pilot-retired at Delta Air Lines (1972-2003)
Updated Oct 1 2018 · Author has 529 answers and 1.1m answer views
I think you meant to say 30 degrees rather than 300 and that the last zero of 300 is supposed to be a degree sign.
If so, the vertical component of the velocity is (sine of 30) times 196= (.5)*196=98 m/s.
The following calculation does not take into account air resistance (aerodynamic drag), which significantly changes the shape of a projectile’s ballistic trajectory.
If we find the time it takes for the bullet’s vertical velocity to decelerate to zero and then double that time (to account for its return to Earth), that is the time of flight.
V=u +at
0= 98m/s + (-9.8 m/s^2) t
-98= -9.8 t
t= 10 sec...
Similar questions