A bullet is fired horizontally with 20 m/s. in the absence of air friction, its horizontal velocity component after 2 second will be;
(*) 40 m/s (*) 20m/s (*) 10 m/s (*) 5 m/s
Answers
Concept
The force preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction. There are several kinds of friction: The force that opposes the relative lateral motion of two solid surfaces in contact is known as dry friction.
Given
A bullet is fired horizontally with 20 m/s. in the absence of air friction is given
Find
We have to find the horizontal velocity component after 2 second.
Solution
The steps are as follow:
- Because of the inertia of motion caused by Newton's First Law of Motion, the bullet's velocity tends to stay constant.
- As a result, the item prefers to continue moving after two seconds since there is no force operating in the opposite direction.
- So the horizontal component will be 20 m/s
Hence the horizontal velocity component after 2 second will be 20 m/s
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Concept:
Friction is the force that prevents solid surfaces, fluid layers, and material constituents from sliding past one another. Different types of friction exist. Dry friction is the resistance to the relative lateral motion of two solid surfaces in contact.
Given:
Without air friction, a bullet is discharged horizontally at 20 metres per second
Find:
After two seconds, we must locate the horizontal velocity component.
Solution:
The following are the steps:
The bullet's velocity tends to remain constant due to Newton's First Law of Motion's inertia of motion.
Since there is no force acting in the opposite direction after two seconds, the object wants to keep going.
Horizontal acceleration must be zero in the absence of air resistance (no forces acting horizontally)
Hence, the horizontal velocity component after 2 seconds will be the same as the initial horizontal velocity. It will be 20m/s after 2 seconds.
Thus, the horizontal velocity component after 2 seconds will be 20m/s.
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