a bullet is fired in upward direction with a intial velocity 25 m/s calculate the distance travelled in upwards direction and time to reach ther
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Answered by
1
given,
velocity=25m/s
required max height reached by bullet.
max height=(v)^2/2g
=25×25÷20
=125/4
=31.25m
hope I was helpful
please mark me brainliest
velocity=25m/s
required max height reached by bullet.
max height=(v)^2/2g
=25×25÷20
=125/4
=31.25m
hope I was helpful
please mark me brainliest
sachanala24:
please mark me brainliest
Answered by
0
Answer:
31.25m
2.5 sec
Step-by-step explanation:
Speed will be 0 at top point
v = u + at
v = 0
u = 25 m/s
a = -g = -10m/s^2 as going upward
0 = 25 - 10*t
t = 25/10
t = 2.5 sec
S = ut + (1/2)at^2
S = 25*2.5 + (1/2)(-10)(2.5^2)
= 62.5 - 5*6.25
= 62.5 - 31.25
= 31.25 m
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