Question

A bullet is fired into a fixed target loses half of its velocity in penetrating 15cm how much further it will be penetrate before com8coming to rest

Answer 1

Answer:

The answer is your question is 5cm

Explanation:

let the consider the 'I'm as the initial velocity of the bullet

U/sar the velocity of the bullet for the initial velocity of the bullet

v^2=u^2+2as

a=-u2/40

Applying the equation of motion for the bullet after penetrating

15cm

v^2=u^2+2as

Here ,U=0 where the bullet is at the rest

The initial velocity of the bullet after penetrating 15cm is u/2

Applying the data in the equation of motion

we get

v^2=u^2+2as

u2/2as=us/4

S=5cm.