Question

A bullet is fired into a huge wooden block. The bullet while moving inside the block loses half the velocity when it travels 6 cm inside the block. How far then would it go inside the block? Resistive force is constant.

Answer 1

Dear Student,

◆ Answer -

x = 2 cm

● Explanation -

As resistant force is constant, retardation will also be constant.

Applying Newton's 3rd law of kinematics -

v^2 = u^2 + 2as

Here, v = u/2, s = 6,

(u/2)^2 = u^2 + 2×a×6

u^2/4 - u^2 = 12a

a = u^2 (1/4-1) / 12

a = -u^2/16

Let x be more depth bullet pierces in wood before stopping.

v'^2 = u'^2 + 2as

0^2 = (u/2)^2 + 2 × -u^2/16 × x

xu^2/8 = u^2/4

x = 2 cm

Therefore, bullet will go 2 cm more in the block (total 8 cm) before stopping.

Thanks dear...

Answer 2

Answer:

short trick is here!!

apply x/n²-1 (formula)

hope it helps you