Question

For what value of 'm' is one zero of the polynomial(m2+9)x2+13x+6m, the

reciprocal of the other?

​

Answer 1

Step-by-step explanation:

Let one of the zero of the polynomial be ß .

Then the other zero will be 1/ß.

ß×1/ß = c/a

ß×1/ß = 6/m^2+9

6m/m^2+9 = 1

m^2+9 = 6m

m^2 - 6m + 9 = 0

m^2-3m-3m+9= 0

m(m-3) - 3(m-3) = 0

(m-3)(m-3) = 0

(m-3)^2=0

m= 3.

I hope this answer will help you.