Question

A bullet is fired vertically upward with a velocity of 196m/s.What is the maximum height reached by bullet

Answer 1

Intial Velocity of Bullet(u) =196m/s
Final Velocity at maximum height will(v)=0 m/s
And Accerlation dur to Gravity (a)=-10m/s
Distance (s)=??

Why We take -10 m/s because it is against Gravity

And We know Newton Equation of motion

V²=U²+2as
0²=196²+2×-10×s
0=38416-20s
20s=38416
S=1920.8 m

Distance =1920.8 m
Approx=1921 m

Maximum Height it reach=1921 m

Answer 2

$initial \: velocity \: (u) = 196 \frac{m}{s} \\ \\ maximum \: height \:(h) = \frac{u {}^{2} }{2g} \\ \\ = \frac{196 \times 196}{2 \times 9.8} = 1960m$