Question

a bullet is fired with a velocity 300m/s in the direction making an angel 45 degree with the horizontal calculate range​

Answer 1

Answer:

This is a simple problem of projectile motion.

Data: Iniatial velocity, u=300 m/s.

Angle of projection , ( theta )= 30^o.

Range, R= ?

Formula: R= 2 u(x)u(y)/g.

u(x) is x- component of initial velocity . u(x) =u cos 30^o=(300)(root 3)/2=259.8 m/s.

u(y) is y- component of initial velocity. u(y)= u sin 30^o= (300)(1/2)=150 m/s.

g is acceleration due to gravity. g=9.8 m/s^2~10m/s^2.

R=(2)(259.8)(150)/10)=7,794 m.