a bullet is fired with a velocity of 150m/s .It penetrates a wood by 5cm and stops. find retardation of the bullet and time interval in which bullet stops
Answers
Answered by
16
v^2=u^2+2as
0^2=150^2 +2a(0.05). [in metres ]
0=22500+0.1a
0.1a=22500
a=-225000m/s^2
retardation is 225000m/s^2
now v=u+at
0=150-225000t
150=225000t
1/t=15*15*1000/150=1500
t=1/1500=0.00066sec
0^2=150^2 +2a(0.05). [in metres ]
0=22500+0.1a
0.1a=22500
a=-225000m/s^2
retardation is 225000m/s^2
now v=u+at
0=150-225000t
150=225000t
1/t=15*15*1000/150=1500
t=1/1500=0.00066sec
Similar questions