Question

A bullet is fired with a velocity of 380 cm per second into a wooden block of thickness 0.19m.it emerges with a velocity of 1.2 metre per second find the acceleration of the bullet

Answer 1

$\huge\underline{\underline{\bf \orange{Question-}}}$

A bullet is fired with a velocity of 380 cm per second into a wooden block of thickness 0.19m.it emerges with a velocity of 1.2 metre per second find the acceleration of the bullet

$\huge\underline{\underline{\bf \orange{Solution-}}}$

$\large\underline{\underline{\sf Given:}}$

• Bullet fire with Velocity ${\sf (u)=380m/s}$

Convert it into m/s

$\implies{\sf u=\dfrac{380}{100} }$

$\implies{\sf u = 3.8m/s }$

• Wooden block of thickness (s) = 0.19m
• It emerges with velocity (v) = 1.2m/s

$\large\underline{\underline{\sf To\:Find:}}$

• Acceleration of bullet (a)

✪$\large{\boxed{\bf \blue{v^2-u^2=2as }}}$

$\implies{\sf (1.2)^2-(3.8)^2=2×a×0.19}$

$\implies{\sf 1.44-14.44=0.38a}$

$\implies{\sf 0.38a=-13}$

$\implies{\sf a=\dfrac{-13}{0.38}}$

$\implies{\bf \red{Acceleration ( a) = -34.2m/a^2}}$

$\huge\underline{\underline{\bf \orange{Answer-}}}$

Bullet will retar d by ${\bf \red{-34.2m/s^2}}$.