Question

A bullet is fixed on a wall with a velocity of 100m/s. If bullet stops at a depth of 10cm inside the wall, then find the retardation produced by the wall

Answer 1

that's the answer hope it helps you

Answer 2

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

★Given :-

u = 100 m/s

v = 0 m/s

s = 10 cm

★Convert 10 cm into m

$\tt{\rightarrow\dfrac{10}{100}=0.1m}$

★To Find :-

v = ?

★Solution :-

$\textbf{\boxed{Third\; Equation\;of\;Motion}}$

${\boxed{v^{2} = u^{2} + 2as}}$

We can also write

${\boxed{a = \dfrac{v^{2}-u^{2}}{2s}}}$

Substitute the values we get :-

$\tt{\rightarrow a =\dfrac{(0)^{2}-{100}^2}{2\times 0.1m}}$

$\tt{\rightarrow\dfrac{-(100\times 100}{0.2}$

= - 50000 m/s²

In km/s² :-

= -50 km/s²

★Here we notice that a means bullet undergoes in retardation.

So,

$\boxed{Retardation\;on\;wall = 50km/s^{2}}$

$\boxed{\begin{minipage}{11 cm} Additional Information \\ \\ \ Distance = Speed\times Time \\ \\ Displacement=Velocity\times time \\ \\ Average\; Speed = \dfrac{Initial\:\:Speed+Final\:\:Speed}{2} \end{minipage}}$