A bullet leaves a rifle with a muzzle velocity of 400 m/s. While accelerating through the
barrel of the rifle, the bullet moves a distance of 0.840 m. Determine the acceleration of the
bullet.
SohamRoy123:
How much time was taken for the bullet to leave the rifle? ithout that, acceleration cannot be found
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The question states that 0.840 m is the distance travelled within the barrel. Therefore u = 0 m/s, v= 521 m/s.
This means that a = (v^2 - u^2)/2s.
This is a reformat of v^2 = u^2 + 2as
a = (521^2)/(2 x 0.840)
a = 161.57 m/s^2
This means that a = (v^2 - u^2)/2s.
This is a reformat of v^2 = u^2 + 2as
a = (521^2)/(2 x 0.840)
a = 161.57 m/s^2
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