a bullet leaves the nozzle of the gun with velocity of 750m/s. assume constant acceleration from the breech to nozzle.find the time occupied by the bullet in travelling through the gun barrel which is 0.75m long?
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The time required is 0.002 s
Explanation:
Given, initial velocity,u= 0 m/s
Final Velocity, v= 750 m/s
a=(v-u)/t
=>a= 750/t
We know
S= 1/2 *a *t^2 when u=0
0.75=1/2 *750/t * t^2
=>t= 0.75*2/750
=>t= 2/1000 =0.002 s
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