A bullet mass 10 g moving with a velocity of 400m/s gets embded in a freely suspended wooden blocks of mass 900g what is the velocity acquired by the block
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hlooo
bullet:-
mass = 10 g = 0.01kg
velocity = 400m/s
wooden block=
mass = 900 g+0.01 kg
=900/1000+0.01=0.91 kg
velocity = v
momentum of bullet = recoil momentum of gun
0.01*400= 0.91*v
4=0.91 *v
v=4/0.91
v= 4.39 m/s answer
hope it help u
bullet:-
mass = 10 g = 0.01kg
velocity = 400m/s
wooden block=
mass = 900 g+0.01 kg
=900/1000+0.01=0.91 kg
velocity = v
momentum of bullet = recoil momentum of gun
0.01*400= 0.91*v
4=0.91 *v
v=4/0.91
v= 4.39 m/s answer
hope it help u
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