if x varies directly as 3y such that when y= 8 and x= 6. finf the value of y, when x= 15
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let x=k × 3y
where k is a proportionality constant
then a/q
6=k ×3×8
so,k=1/4
hence ,15=1/4×3×y
so, y=15×4/3=20 and
thanks.plz mark it as brainliest .
where k is a proportionality constant
then a/q
6=k ×3×8
so,k=1/4
hence ,15=1/4×3×y
so, y=15×4/3=20 and
thanks.plz mark it as brainliest .
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