Question

A bullet moving at the rate of 300 m/s is fired into a thick target and

penetrates up to 500 mm. If it is fired into a 250 mm thick target, find the

velocity of emergence. Take resistance to be uniform in both cases.​

Answer 1

Answer:

In the first case the initial velocity(u) = 80 m/s and distance travelled(s) = 50 cm.

But, here the final velocity =0, thus

0=u

2

−2as ( negative sign because some resistive force is acting )

a=6400m/s

2

In the second case case acceleration (a)=6400m/s

2

Substituting in equation, we have

v

1

2

=u

1

2

−2as

1

=(80)

2

−2×6400×

4

1

=6400−3200

=3200 or v

1

=40

2

The emerging velocity is 40

2

m/s.

Explanation:

may be it helps you