a bullet moving with 10 M per second hits a wooden plank the bullet stop when it penetrate the prank 2 cm deep. calculate the retardation of the bullet
priyanshu7777:
which class question is this?
can you tell me the formulae how to find retardation?
please answer me
Ohh no need I understood -acc.
Answers
Answered by
128
Given, the bullet is moving with a speed of 10m/s
=> u = 10 m/s
It stops after penetrating a wooden plank 2 cm deep.
=> v = 0 m/s (since it stops)
s = 2 cm
Convert cm to m,
2cm = 2/100 m = 0.02 m
Now, we have to find the retardation, that I, the negative acceleration.
From the third equation of motion, we have
v² - u² = 2as
Put the values to get the retardation.
=> (0)² - (10)² = 2a × 0.02
=> -100 = 0.04 a
=> a = -100/0.04
=> a = - 2500 m/s²
Answer :-
=> u = 10 m/s
It stops after penetrating a wooden plank 2 cm deep.
=> v = 0 m/s (since it stops)
s = 2 cm
Convert cm to m,
2cm = 2/100 m = 0.02 m
Now, we have to find the retardation, that I, the negative acceleration.
From the third equation of motion, we have
v² - u² = 2as
Put the values to get the retardation.
=> (0)² - (10)² = 2a × 0.02
=> -100 = 0.04 a
=> a = -100/0.04
=> a = - 2500 m/s²
Answer :-
thank You again
this is so easy!!!!!!!!!
my pleasure
thAnk yuo
so you have the opportunity and you
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he is brilliant I can't answer as he did.
but I can try
Thanks all
don't understand what do not hesitate you can do
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a bullet moving with 10 M per second hits a wooden plank the bullet stop when it penetrate the prank 2 cm deep. calculate the retardation of the bullet=2500ms
hi mark as brain list
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