a bullet moving with 20m/s strikes a target and comes to rest after penetrating 10cm calculate the retardation
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Answered by
21
Here Initial velocity = 20m/s
final velocity =0
distance =10 cm =0.1 m
acceleration =a=?
using v^2-u^2=2as
0^2 - 20^2=2a×0.1
-400=0.2a
-400/0.2=a
therefore a=-2000m/s^2
negative sign shows the retardation
final velocity =0
distance =10 cm =0.1 m
acceleration =a=?
using v^2-u^2=2as
0^2 - 20^2=2a×0.1
-400=0.2a
-400/0.2=a
therefore a=-2000m/s^2
negative sign shows the retardation
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Answered by
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retardatiom= - 2000 m/s^
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