a bullet moving with a velocity of 100m/s strikes a wooden plank. it penetrates the plank to a depth of 20cm calculate tge average retardation
Answers
The average retardation is 25000 m/s².
Given: The initial velocity of a bullet = 100 m/s,
The distance penetrated = 20 cm.
To Find: The average retardation.
Solution:
- We can solve the numerical using the formula of motion,
v² = u² + 2aS .....(1)
Where v = final velocity, u = initial velocity, a = acceleration, S = distance
- Since, the bullet stops after penetrating 20 cm, the final velocity is zero.
Coming to the numerical, we have;
The initial velocity (u) = 100 m/s
The final velocity (v) = 0
The distance penetrated (S) = 20 cm = 0.2 m
Putting respective values in (1), we get;
v² = u² + 2aS
⇒ 0² = 100² + 2 × a × 0.2
⇒ a = - ( 100 × 100 ) / 0.4
⇒ a = - 25000 m/s²
The negative sign means that the bullet is decelerating or retarding.
Hence, the average retardation is 25000 m/s².
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Answer:
25000 m/s².
Explanation:
Given: Initial velocity of a bullet = 100 m/s,
Distance penetrated = 20 cm.
To Find: Average Retardation.
Using the third law of motion,
v² = u² + 2aS .....(1)
Where v = final velocity, u = initial velocity, a = acceleration, S = distance
The final velocity is zero since the bullet stops after traversing a distance of 20 cm.
We have, u = 100 m/s
v = 0
S = 20 cm = 0.2 m
Putting values in equation (1), we get;
v² = u² + 2aS
⇒ 0² = 100² + 2 × a × 0.2
⇒ a = - ( 100 × 100 ) / 0.4
⇒ a = - 25000 m/s²
The bullet is retarding or decelerating when the sign is negative.
The average retardation is therefore 25000 m/s².
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