Physics, asked by kavithadevi0435, 8 months ago

A bullet moving with a velocity of
20 m/s hits a sand bag and come
to rest after penetrating 5 cm into
the bag then the retardation offered
by the sand bag will be:
A.
400 m/s2
B
4000 m/s2
C
40 m/s2
4000 cm/s2
D​

Answers

Answered by Anonymous
2

Answer:

4000 m/s² is your answer

I don't think you need explanation because you haven't mentioned.

Steps: convert 5cm to m

And then use the formula v²=u²+2as

Answered by avanigarg1869
2

Answer:

(b) 4000m/s2

please mark my answer as brainliest.......

hope it would be helpful.

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