Question

a bullet moving with velocity of 10m/s is brought to rest after penetrating the wooden plank of 4 cm thickness . calculate the acceleration of the bullet

Answer 1

the acceleration of the bullet is -1250m/s^2.

Answer 2

Answer:

The amount of retardation is -1250m/s.

Explanation:

Acceleration exists at the rate at which velocity varies with time, in terms of both speed and direction. A point or an object moving in a straight line exists accelerated if it speeds up or slows down.

Velocity exists as the rate of change of displacement. Acceleration exists in the rate of change of velocity. Velocity exists as a vector quantity because it consists of both magnitude and direction. Acceleration exists also as a vector quantity as it stands only at the rate of change in velocity.

Stopping distance S = 4 cm

= 0.04 m

initial velocity = 10 m/s

final velocity = 0 (since object stops)

we know

$v^{2} -u^{2} = 2as$

$10^2 + 2a*0.04 = 0$

$10^2 + 2a*0.04 = 0$

$a = -1250 m/s.$ is the amount of retardation.

Therefore, the amount of retardation is -1250m/s.

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