Question

a bullet moving with velocity of 200 m/s pierced 100 cm through a wooden block.what is its deceleration​

Answer 1

Answer:

-40000m/s^2

Explanation:

time = distance/speed

= 1m/200m/s= 0.005s

v = u + at

u = 200m/s, t = 0.005s, v = 0

0 = 200 + a(0.005)

a = -200/(0.005)

= -40000m/s^2