Question

A bullet of 10 gram strikes A sand bag at a speed of 10^3 metre / second and gets embedded after travelling 5 cm s calculate the resistive force exerted by the sand on the bullet and the time taken by bullet to come to rest

Answer 1

hey there !!!

let's see ,, how can we solve it :-

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the depth of bullet = 5cm = 0.05cm

mass of bullet = 10gm = 0.01 kg

now by third eqn. of motion :-

v²– u²= 2as

0 – 1000×1000 = 2 × a ×0.05

a = –10000000 m/s²

here -ve sign indicates that acceleration is opposite to the motion.

now ,

a). force = ma 
= 0.01 × 10000000
= –100000 N

b). time taken by the bullet to get stopped

=> v = u + at

=> 0 = 1000 – 100000×t

1000 = 100000 × t

=>t = 0.01 sec

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and , that's it !

hope it helps !!

be happy and be brainly !! ☺☺