Question

A bullet of 10g moving with a speed of 100m/s penetrates a sand bag and comes to rest in 0.1 seconds .Find (a) the distance through which the bullet penetrates (b) the retarding force experienced.

Answer 1

Answer:

mass of bullet =10g=0.01kg

acceleration of bullet =(v-u)/t

= (0-100)/0.1=-1000 m/s2

from equation of motion

v2-u2=2aS

0-10000=2×-1000 S

S=5m

force =m(v-u)/t

=0.01×(0-100)/0.1

=-10N

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Answer 2

(I) 5 m

(II) -10N

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