a bullet of 20 gram is horizontly fired with a velocity of 150.0 meter per second from a pistol of mass 2 kg. what is the recoil velocity of the pistol
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GIVEN
- Mass = 20g = 0.02 kg
- Initial velocity (u) = 150 m/s
- Final velocity (v) = 0 m/s
SOLUTION
Distance travelled before coming to rest (s) = 10 cm=0.1 m
FORMULA USED
»» v² = u² - 2as « m«
⇒0=(150)² −2⋅a⋅0.1 = 112500 m/s²
»» f = ma ««
⇒f=0.02×112500 =2250 N
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