A bullet of 4g when fired with a velocity of 50m/s can enter a wall hoti a depth of 10cm. How much will be the average resistance offered by the wall
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A bullet of 4gm fired from a gun with a velocity of 50 m/s enters a wall upto a death of 10 cm, what is the average resistances offered by the wall?
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Ankit Sharma, Faculty Member (Physics) at Allen Career Institute, Kota (2015-present)
Answered Sep 15, 2016
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For the motion of bullet inside wall,
a = (v^2 - u^2)/2S
Where,
v = final velocity = 0 m/s
u = initial velocity = 50 m/s
S = displacement = 10cm = 0.1 m
Therefore acceleration comes out to be, a = 12,500 m/s^2.
From F=MA
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Ankit Sharma, Faculty Member (Physics) at Allen Career Institute, Kota (2015-present)
Answered Sep 15, 2016
Continue Reading
For the motion of bullet inside wall,
a = (v^2 - u^2)/2S
Where,
v = final velocity = 0 m/s
u = initial velocity = 50 m/s
S = displacement = 10cm = 0.1 m
Therefore acceleration comes out to be, a = 12,500 m/s^2.
From F=MA
unnikannan:
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Answer:
a= v²-u²/2s
a = 0²-50²/2×0.1
a= -2500/2×0.1
a=12,500 m/s ²
force=Mass ×Acceleration
=0.004 × 12500
=50 N
Hope it helps !♡
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