Physics, asked by Anjalilekhak2003, 1 year ago

A bullet of 4g when fired with a velocity of 50m/s can enter a wall hoti a depth of 10cm. How much will be the average resistance offered by the wall

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Answered by unnikannan
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A bullet of 4gm fired from a gun with a velocity of 50 m/s enters a wall upto a death of 10 cm, what is the average resistances offered by the wall?

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Ankit Sharma, Faculty Member (Physics) at Allen Career Institute, Kota (2015-present)

Answered Sep 15, 2016

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For the motion of bullet inside wall,

a = (v^2 - u^2)/2S

Where,

v = final velocity = 0 m/s

u = initial velocity = 50 m/s

S = displacement = 10cm = 0.1 m

Therefore acceleration comes out to be, a = 12,500 m/s^2.

From F=MA

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Answered by sarojini0077
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Answer:

a= v²-u²/2s

a = 0²-50²/2×0.1

a= -2500/2×0.1

a=12,500 m/s ²

force=Mass ×Acceleration

=0.004 × 12500

=50 N

Hope it helps !

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