Question

A bullet of 60 gm is fired using a rifle of mass 12 kg. Rifle recoils with a velocity of 2.5 m/s. Calculate initial velocity of the bullet.​

Answer 1

• We know that velocity of rifle×mass of rifle=..velocity of bullet×mass of bullet
• So we get 60 × x=12 × 2.5
• So we get x=12×2.5/60
• So x=0.5m/s

Answer 2

Answer:

500 m/s

Explanation:

$m_1$ = Mass of bullet = 0.06 kg

$m_2$ = Mass of rifle = 12 kg

$v_1$ = Final Velocity of bullet

$v_2$ = Final Velocity of rifle = 2.5 m/s

Since both the bullet and rifle start from rest

$m_1v_1=m_2v_2\\\Rightarrow v_1=\frac{m_2v_2}{m_1}\\\Rightarrow v_1=\frac{12\times 2.5}{0.06}\\\Rightarrow v_1=500\ m/s$

The velocity of the bullet is 500 m/s