Question

a bullet of comes out of the barallel of gun of length 2m with a speed of 800m/s the avarage acceleration of the bullet

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Answer 1

Question :

A bullet of comes out of the barrel of gun of length 2m with a speed of 800m/s the average acceleration of the bullet .

Given :

• Length of gun (s) = 2 m
• Initial velocity (u) = 0 m/s [∵ As it was at rest before firing]
• Final velocity (v) = 800 m/s

To find :

• Acceleration of bullet

Solution :

From the third equation of motion we get,

⇒ v² - u² = 2as

Substituting values,

⇒ 800² - 0² = 2 * a * 2

⇒ 640,000 - 0 = 4a

⇒ 640,000 = 4a

⇒ a = 640,000/4

⇒ a = 160,000 ms⁻²

⇒ a = (160,000)/1000 km/s²

⇒ a = 160 km/s²

∴ Acceleration of bullet = 160000 m/s² or 160 km/s²

Answer 2

Answer:

• The average acceleration of the bullet is 160000 m/s².

Explanation:

Given that,

• Length of gun (s) = 2 m
• Initial velocity (u) = 0 m/s
• Final velocity (v) = 800 m/s

Applying 3rd eqn. of motion,

$\purple\bigstar$ v² = u² + 2as

[ Putting values ]

↪ 800² = 0² + 2 × a × 2

↪ 64000 = 4a

↪ a = 640000/4

↪ a = 160000 m/s² $\red\bigstar$

For information:

• v = u + at
• s = ut + 1/2 at²