a bullet of mas 10 g strikes a sand bag
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A bullet of 10g strike the sand bag at a speed of 1000m/s and gets embedded after travelling 5cm.calculate
(a)Resistive force exerted by sand on bullet.
(b)Time taken by bullet to come to rest.
I suppose this is the question then the answer is
the depth of bullet = 5cm = 0.05cm
mass of bullet = 10gm = 0.01 kg
now by third eqn. of motion
v^2 – u^2 = 2as
0 – 1000×1000 = 2 × a ×0.05
a = –10000000 m/s^2
here -ve sign indicates that acceleration is opposite to the motion.
now a). force = ma
= 0.01 × 10000000
= –100000 N
b). time taken by the bullet to get stopped
= v = u + at
=> 0 = 1000 – 100000×t
1000 = 100000 × t
=>t = 0.01 sec
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(a)Resistive force exerted by sand on bullet.
(b)Time taken by bullet to come to rest.
I suppose this is the question then the answer is
the depth of bullet = 5cm = 0.05cm
mass of bullet = 10gm = 0.01 kg
now by third eqn. of motion
v^2 – u^2 = 2as
0 – 1000×1000 = 2 × a ×0.05
a = –10000000 m/s^2
here -ve sign indicates that acceleration is opposite to the motion.
now a). force = ma
= 0.01 × 10000000
= –100000 N
b). time taken by the bullet to get stopped
= v = u + at
=> 0 = 1000 – 100000×t
1000 = 100000 × t
=>t = 0.01 sec
Read more on Brainly.in - https://brainly.in/question/1255343#readmore
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