Physics, asked by arafat4599, 11 months ago

A bullet of mass 0.005 kg travelling at 150 m/s penetrate a fixed wooden block for 1/10 second.Calculate the distance of the penetration of the block and average retardation force on the bullet

Answers

Answered by vivek21vv
42

Answer:

distance penetrated = 7.5 m, average retardation force = 7.5 N

Explanation:

Given that,

Mass of the bullet is 0.005 Kg.

Initial velocity of the bullet is 150 m/s.

Time of penetration is 1/10 sec.

Final velocity of the bullet is 0 m/s.

So,

distance of penetration = ut + 1/2at^2

s = 150(1/10) + 1/2[(0-150)/1/10](1/10)^2

s = 7.5 m

average retardation force = mass * acceleration of retardation

                                       F = m*a

                                          = 0.005*(0-150)/(1/10)

                                          = 7.5 N

Answered by Anonymous
1

Answer:

Explanation:

In physics, the Coriolis force is an inertial or fictitious force that acts on objects that are in motion within a frame of reference that rotates with respect to an inertial frame. ... Newton's laws of motion describe the motion of an object in an inertial (non-accelerating) frame of reference.

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