A bullet of mass 0.005 kg travelling at 150 m/s penetrate a fixed wooden block for 1/10 second.Calculate the distance of the penetration of the block and average retardation force on the bullet
Answers
Answer:
distance penetrated = 7.5 m, average retardation force = 7.5 N
Explanation:
Given that,
Mass of the bullet is 0.005 Kg.
Initial velocity of the bullet is 150 m/s.
Time of penetration is 1/10 sec.
Final velocity of the bullet is 0 m/s.
So,
distance of penetration = ut + 1/2at^2
s = 150(1/10) + 1/2[(0-150)/1/10](1/10)^2
s = 7.5 m
average retardation force = mass * acceleration of retardation
F = m*a
= 0.005*(0-150)/(1/10)
= 7.5 N
Answer:
Explanation:
In physics, the Coriolis force is an inertial or fictitious force that acts on objects that are in motion within a frame of reference that rotates with respect to an inertial frame. ... Newton's laws of motion describe the motion of an object in an inertial (non-accelerating) frame of reference.