A bullet of mass 0.02kg is fired from a gun veying 7.5kg . If the initial velocity of bullet is 200m/s-1 .calculate the speed with which the gun recoils
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m₁ = 0.02 kg
m₂ = 7.5 kg
u₁ = 0
u₂ = 0
v₁ = 200 m/s
v₂ = v
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.02 * 0 + 7.5 * 0 = 0.02 * 200 + 7.5 * v
0 = 4 + 7.5 v
-4 = 7.5 v
v = 7.5 / 4 = 1.875 m/s
Recoil velocity of gun = 1.875 m/s
m₂ = 7.5 kg
u₁ = 0
u₂ = 0
v₁ = 200 m/s
v₂ = v
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.02 * 0 + 7.5 * 0 = 0.02 * 200 + 7.5 * v
0 = 4 + 7.5 v
-4 = 7.5 v
v = 7.5 / 4 = 1.875 m/s
Recoil velocity of gun = 1.875 m/s
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