A bullet of mass 0.02kg is horizontally fired with a velocity of 200 m/s from a
pistol of mass 4 kg. Calculate the recoil velocity of the pistol.
Answers
Answered by
1
Answer:
initial momentum of the system is 0 as it is at rest
After firing -
MV= mv
V=mv/M = 0.02×150
2
V= 1.5m/s
Answered by
3
Answer:
V=1.5m/s...........
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