A bullet of mass 0.02kgm is fired from a gun of weight 7.5kg.If the initial velocity is 200 m per sec.Calculate the speed of the gun recoil
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7.5 × 200 = 150 m/s..........
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ACC to law of conservation of momentum
mass of bullet×velocity of bullet=mass of gun × velocity of gun
0.02×200=7.5× X
X= 0.53ms^-1
mass of bullet×velocity of bullet=mass of gun × velocity of gun
0.02×200=7.5× X
X= 0.53ms^-1
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