A bullet of mass 0.04 kg is fired from a gun weighing 9.5kg. if the initial velocity of bullet is 400m/s calculate the speed at which the gun recoils
Answers
Answered by
2
Answer:
V= 1.6842 m/s
Explanation:
M= mass
V= velocity
MV= -MV (negative because of opposite direction)
MV + MV = 0
V= velocity of gun recoiling
(0.04 X 400) + (9.5 X V) = 0
16 + 9.5V= 0
9.5V= -16
V= 16/9.5 (Negative sign is removed because it is for showing direction, and that's not needed any more.)
V= 1.6842 m/s
Similar questions