A bullet of mass 0.3kg is fired from a gun of mass 6kg with a velocity 300m/s. Calculate the recoil velocity of the gun?
Answers
Answered by
1
Answer:
v= 15m/s
Explanation:
using conservation of momentum
mass of gun × velocity of gun = mass of bullet× velocity of bullet
=> (6)×v = (0.3) ×(300)
=> v = 90/6
=> v = 15m/s
Answered by
1
Answer:
let the recoil velocity be v2
m1=0.3kg, m2=6kg
u1=0m/s, u2=0m/s
v1=300m/s, v2=unknown
ACCORDING OF LAWS OF CONSERVATION OF MOMENTUM (m1u1+m2u2)=(m1v1+m2v2)
A/Q 0+0=(0.3×300+6×v2)
-90=6×v2
v2= -90/6
v2= -15m/s ANS.
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