Question

quadratic polynomial x2-2x-8 has alpha and beta now form a quadratic polynomial whose zeroes are ​

Answer 1

Answer:

hey mate.. this is your answer

Step-by-step explanation:

Given α and β be the zeroes of polynomials, so the quadratic polynomial is x

2

−(α+β)x+αβ , comparing the above equation to the given equation, x

2

−2x−8, so we have,

α+β=2 and αβ=−8

So, 3α+3β=3(α+β)=3×2=6 and 3α×3β=9αβ=9×(−8)=−72

Thus, the required quadratic polynomial is x

2

−3(α+β)x+9αβ

Putting the values of α+β and αβ in above equation, x

2

−6x−72

hope you have a good day