Question

A bullet of mass 10 g is fired horizontally with a velocity 200 m/s from a pistol of mass 2 kg. Calculate the recoil velocity of the pistol.​

Answer 1

Answer:

-1 m/s

Explanation:

According to the law of conservation of momentum m1u1+m2u2=m1v1+m2v2

Therefore initial momentum of the system ( bullet+pistol) = 0

And finial momentum of the system (bullet+pistol) = 2kgm/s+2V

So, 2kgm/s +2V=0

Or 2+2V=0

Therefore recoil velocity of the pistol = -1 m/s