Question

A bullet of mass 10 g is horizontally fired with a velocity 300 m/s from a pistol of mass 3 kg. Calculate recoil velocity of the pistol?

A) 2m/s

B) 3m/s

C) 2.5m/s

D) 1m/s​

Answer 1

Answer :

➥ The recoil velocity of the pistol = 1 m/s

Given :

➤ Mass of the bullet (m₁) = 10 g

➤ Velocity of the bullet (v₁) = 300 m/s

➤ Mass of the pistol (m₂) = 3 kg

To Find :

➤ Recoil velocity of the pistol (v₂) = ?

Solution :

• Mass of the bullet (m₁) = 10 g = 0.01 kg

As we know that

$\tt{: \implies m_1\: v_1 = m_2 \: v_2}$

$\tt{: \implies 0.01 \times 300 = 3 \times v}$

$\tt{: \implies 3 = 3 \times v}$

$\tt{: \implies 3 \times 3v}$

$\tt{: \implies v = \dfrac{3}{3} }$

$\tt{: \implies \green{\underline{ \overline{ \boxed{ \purple{ \bf{ \: \: v = 1 \: m/s \: \: }}}}}}}$

Hence, the recoil velocity of the pistol is 1 m/s.

Answer 2

Explanation:

What is the work required to increase the velocity of car from 36 km/h to 108 km/h, if the mass of the car is 1200 kg?