a bullet of mass 10 g moves with the speed of 100m/s² and gets embedded in a sand bag after traveling 5 cm
what is the resistance by the sand bag on the bullet
Answers
QUESTION :
a bullet of mass 10 g moves with the speed of 100m/s² and gets embedded in a sand bag after traveling 5 cm
what is the resistance by the sand bag on the bullet
Explanation:
Mass of bullet should be =10gm=0.01kg
initial velocity (U)of bullet=1000m/s
final velocity (V)=0m/s(because it has stopped after striking sand)
displacement of bullet=5cm=0.05m
a)using 2as=V ²-U²
2(a)(0.05)=0²-1000²
2a(5/100)=-1000000
2a(1/20)=-1000000
a(1/10)=-1000000
a=-10000000=-10power7
acceleration of bullet is -10power7or -10000000
by using F=ma
F=0.01(10000000)
F=1/100(10000000)
F=-100000N
there fore resistive force of bullet =-100000N
b)by using a=v-u/t
-10000000=0-1000/t
-10000000=-1000/t
-10000=t
or
t=-10⁴seconds
Answer:
Answer
v
2
=u
2
+2as
0=(10
3
)
2
+2×a×(5×10
−2
)
a=−10
7
m/s
2
v=u+at
0=10
3
−10
7
×t
t=10
−4
s