Question

A bullet of mass 10 g moving with a velocity of 400m/s gets embedded in a freely suspended wooden block of mass
900 g. what is the velocity acquired by the wooden block????
plzzzzzzzz tmorrw is my exam do it fast.

Answer 1

hope your ans is right and and plz make it brain list

answer:4.4m/s 
reason:
let the final velocity of the bullet embedded in it be v
according to the law of conservation of momentum,

total momentum before
collision = total momentum after collision 
=

0.001* 400+0.9*0/0.001 + 0.9 = 4/0.91 = 400/91 =

4.4 m/s

Answer 2

By using law of conservation of momentum
m₁u₁ = (m₁ + m₂)v

v = m₁u₁ / (m₁ + m₂)
= (10 × 10^-3 kg × 400 m/s) / [(10 + 900) × 10^-3 kg]
= 4.395 m/s

Velocity acquired by the wooden block is 4.395 m/s