Question

A bullet of mass 10 g traveling horizontally with a velocity of 150 m per second strikes stationery wooden blocks and comes to rest in 30.0 3 seconds calculate the distance of p********** of the bullet into the block also calculate the magnitude of the force exerted by the wooden block on the bullet

Answer 1

Please find your answer below

Answer 2

mass of the bullet (m) = 10 g = (10/1000) kg =0.01 kg Initial velocity (u) = 150 m/s Final velocity (v) = 0 m/s Time taken (t) = 30.03 sec

Calculation of the distance of penetrationof the bullet into the block = Displacement Displacement = average velocity × time Displacement = [(u + v) / 2] × time Displacement = [(150 + 0) / 2] × 30.03=2252.25

The magnitude of the force exerted by the wooden block on the bullet = Retarding force Retarding force = mass × reatardation Retarding force = mass ×[ (Intitial velocity - Final velocity) / t ]Retarding force = 0.01 ×[ (150 - 0) / 30.03 ] = 1.5

therefore the magnitude of the force exerted by the wooden block on the bullet is 1.5 N