A bus at rest accelerates uniformly to a velocity 54 km/h in 20s how much distance is travelled by the bus in 20s
Answers
Given v = 54 km / h = 54 × 5/18 = 15 m/s u = 0 t = 20 sec a = v - u /t = 15 - o/ 20 = 0.75 ms-1 S= ut + 1/2 at2 S = 0× 20 + 1/2 × 0.75 × 20×20 = 150 m
Concept:
The rate at which an object's velocity with respect to time changes is called its acceleration.
Velocity is the direction at which an object is moving and serves as a measure of the pace at which its position is changing as seen from a specific point of view and as measured by a specific unit of time.
Given:
Initially, the bus is at rest and uniformly accelerates to a velocity of 54 km/h in 20 seconds.
Find:
The distance traveled by bus in 20 seconds.
Solution:
The initial velocity of the bus, u = 0 km/h
The velocity of the bus after t = 20 seconds, v = 54 km/h = 15 m/s
Using the equation motion,
v = u + at
15 = 0 + a(20)
a = 0.75 m/s²
Now,
S = ut + (1/2)at²
S = 0 + (0.5)(0.75)(20)²
S = 150 m
The distance traveled by bus in 20 seconds is 150 meters.
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