Question

A bullet of mass 10 g travelling horizontally with a velocity of 150 m strikes a stationary wooden block and comes to rest in 0.03 s. Calculate the distance of penetration of the bullet into the block. Also calculate the magnitude of the force exerted by the wooden block on the bullet. ​

Answer 1

Answer:

s= 2.25m

F= -50 N

Negative sign shows that force is in opposite direction to the bullet.

Explanation:

m=10g=0.01 kg

u=150m/s

v=0m/s (It comes to rest)

t=0.03s

a=?

We know that,

a=v-u/t

a=0-150/0.03

a = -150/0.03

a =-5000 m/s^2

According to 3rd equation,

v^2 = u^2 +2as

0= 150^2 +2(-5000)(s)

-22500= -10000s

-22500/-10000=s

s= 2.25m

We know that,

F=ma

F= 0.01 × -5000

F = -50 N

Negative sign shows that force is in opposite direction to the bullet.