Question

A bullet of mass 10 gm moving horizontally at 400 m/s gets embedded in a wooden block of mass 900gm. What is velocity acquired by the block?

Answer 1

Answer:

4.4m/s

Explanation:

It is purely related to conservation of linear momentum

therefore before collision 10gms*400m/s = 4000gm*m/s

after collision 900gm * v

we must find v so we equate both of them

4000 = 900*v

v = 4000/900

v = 4.4 m/s