Question

A bullet of mass 10 gram moves along with the velocity of 400 metre per second gets embedded in a stationary wooden block of 900 gram what is the velocity acquired by the block


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Answer 1

Here is your answer-
M of bullet =10g=0.001 kg
M of block=900g=0.9 kg
U of bullet = 400m/s
V of bullet = 0m/s
U of block =0m/s
V of block= Vw
According to law of conservation of momentum

Total initial momentum =Total final momentum
Initial momentum of bullet + Initial momentum of block = Final momentum of bullet + Final momentum of block
0.001*400 + 0.9*0 = 0.001*0 + 0.9*Vw
=0.4-0.001=0.9Vw
0.399=0.9Vw
4.4m/s=Vw