Question

A bullet of mass 10 gram strikes a wooden Block with a velocity of 300 metre per second after penetrating 20 cm into it its velocity drops to 200 metre per second then average resistance offered by the blockage ​

Answer 1

Answer:

I don't know what is answer

but I think 500 per second

Answer 2

The resistance force is 1250 N.

Explanation:

Given that,

Mass of bullet = 10 gram

Initial velocity of bullet = 300 m/s

Final velocity = 200 m/s

Distance = 20 cm

We need to calculate the acceleration

Using equation of motion

$v^2=u^2+2as$

$a=\dfrac{v^2-u^2}{2s}$

Put the value into the formula

$a=\dfrac{200^2-300^2}{2\times20\times10^{-2}}$

$a=-125000\ m/s^2$

It is a retardation.

We need to calculate the resistance force

Using formula of resistance force

$F = ma$

$F=10\times10^{-3}\times(125000)$

$F=1250\ N$

Hence, The resistance force is 1250 N.

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Topic : resistance force

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