Question

A bullet of mass 10g is fired from a gun of mass 6kgwith a velocity of 300m/s

Answer 1

Answer:

Explanationgun:-.

bullet:-

m1= 6kg m2=10g=0.01kg

u1= 0. u1=300m/s

v=? v2 =0

initial momentum = 6*0+1/100*300

=>3kg m/s

final momentum= 6*v+1/100*0

=>6v

so recoil velocity of gun

= final momentum= -(initial momentum)

=> 6v=-3

=> v= -3/6

= -1/2m/s

Answer 2

by using momentum formula...u will get the ans.