Question

A bullet of mass 10g is fired horizontally with a velocity of 150m/s from a gun of mass 4kg. Calculate the recoil velocity of gun.

Answer 1

Answer:

-0.375m/s

Step-by-step explanation:

by conservation of momentum we know that

initial momentum = final momentum

let m1 be the mass of bullet and m2 be the mass of the gun.

m1u1 + m2u2= m1v1 + m2v2

also we know that initially the gun as well as the bullet are at rest .....hence

0=m1v1+m2v2

also SI unit is kg

mass of bullet =m1=10 g = 0.01kg

velocity of bullet=v1=150m/s

mass of gun=m2=4kg

so.....

0=(0.01*150)+4 v2

4v2= -1.5

v2=-(1.5)/4

= -0.375m/s

negative sign represents that it will recoil in a direction opposite to that of the bullet fired

pls mark it the brainliest...

by the way I am also in 9th

Answer 2

Given:

• Mass of Bullet (m1)= 10g
• Velocity of Bullet ( v1) = 150 m/s
• Mass of gun (m2) = 4kg

To Find:

• Recoil velocity of Gun?

Solution:

Mass of bullet is 10g

=> 1kg = 1000 g

=> kg = 10/1000

=> kg = 0.01 kg

$\bigstar{\underline{\underline{\boxed{\sf{ \green{Momentum_{(Bullet)} } = \blue{Momentum_{(Gun)} } }}}}}$

$\bigstar{\underline{\boxed{\sf{ Momentum = Mass \times Velocity }}}}$

Where

• p = Momentum
• m = Mass
• v = Velocity

After putting the Values,

➙ m × v = m × v

➙ 0.01 × 150 = 4 × v

➙ 1.5/4 = v

➙ v = 0.375 m/s

Hence,

• The Recoil Velocity of Gun is 0.375 m/s.

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